Question

5. The parallel sides of a trapezium are 65 m and 40 m. Its non-parallel sides are
39 m and 56 m. Find the area of the trapezium.​

Answer 1

Answer:

Step-by-step explanation:

Hey there!

x²+h² = 56²  

(25-x)²+h² = 39²  

x²-56² = (25-x)² - 39²  

x = 224/5  

So,

h² = 56²-x² = 28224/25  

h = 168/5  

Thus,

The area is (40+65)/2 × 168/5 = 1764

Cheers!

Answer 2

Draw the figure. If the height is h, then you have a 40-by-h rectangle in the center, with extra lengths of x and 25-x on the longer base.

x^2+h^2 = 56^2

(25-x)^2+h^2 = 39^2

x^2-56^2 = (25-x)^2 - 39^2

x = 224/5

so, h^2 = 56^2-x^2 = 28224/25

h = 168/5

so, the area is (40+65)/2 * 168/5 = 1764

$bts \: forever$