Question

5.
The perimeter of a rhombus is 68 cm and the length of one of its diagonal is 16 cm. Fin
length of the other diagonal and area of the rhombus.
6.
The area of
no​

Answer 1

Answer:

240cm square

Step-by-step explanation:

4a = 68 => a = 17

172 - 82 = 152

1/2 × 16 × 30 = 240cm square

Answer 2

Answer:

30 cm

Step-by-step explanation:

5) Let ABCD is a rhombus in which diagonals AC and BD cut at O , AC=16 cm, AO=AC/2=16/2=8cm.

perimeter=4×side

68 cm=4×x => x=17 cm

AB=BC=CA=AD=x=17 cm.

In right angled triangle AOD:-

(AO)^2+(OD)^2=(AD)^2

(8 cm)^2+(BD/2)^2=(17 cm)^2

(BD/2)^2=289 cm^2–64 cm^2

(BD/2)^2=225 cm^2

BD/2=15 cm

BD=30 cm , Answer.

6) no question you have not written it full