Question

5. The perimeter of a triangle is 6x2 - 4x + 9 and two of its sides are x2 - 2x +1 and
3x2–5x + 3. Find the third side of the triangle ​

Answer 1

Answer:

perimeter = sum of sides

x²-2x+1+3x²-5x+3+a = 6x²-4x +9

x²+3x²-6x²-2x-5x+4x+1+9+a = 0

-2x²-3x+10+a = 0

2x²+3x-10-a = 0

a = 2x²+3x-10

Therefore the third side is 2x²+3x-10

Answer 2

Step-by-step explanation:

Let the third side be a.

perimeter = sum of sides

x²-2x+1+3x²-5x+3+a = 6x²-4x +9

x²+3x²-6x²-2x-5x+4x+1+9+a = 0

-2x²-3x+10+a = 0

2x²+3x-10-a = 0

a = 2x²+3x-10

Therefore the third side is 2x²+3x-10

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