5. The pH of HCl is 5. It is diluted by 1000 times
Its pH will be
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8
by concept of millimoles
M1*V1 = M2*V2
since pH = 5 , so concentration of H+ is molarity = 10^-5M , V2 = 1000*V1
so M2 =10^-8 but since [H+] = 10^-8
pH = 8 [can not be 8 for acid ]
so here when concentration of HCl is less than 10^-6M , we have to consider concentration of H+ = 10^-7M from water.
so Total [H+] = 10^-7 +10^-8
[H+] = 1.1*10^-7
now take negative of logarithm to base 10
pH = 7 - log(1.1 with base 10)
pH = 7 -0.04 = 6.96
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3
pH of HCl would be 7.
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