Question

5. The population of a town increases at the rate of 40 per thousand. Its population after 2 years will be
6084. Find its present population. ​

Answer 1

◆ Answer -

[tex]\sf{Present~ population = 5625 }[/tex]

● Explanation -

$\sf{Let ~'x'~ be~ present~ population~ of ~the ~town.}$

$\sf{Population~ after~ 2 ~years ~is ~given~by:}$

$\tt{P' = P (1 + r)^t}$

[tex]\tt{6084 = P \frac({1 + 40}{1000})^2 }[/tex]

$\tt{6084 = P (\frac{1 + 40}{1000})^2}$

$\tt{6084 = P (\frac{1 + 1}{25})^2}$

$\tt{6084 = P × (\frac{26}{25})^2}$

$\tt{P = 6084 × \frac{625}{676}}$

$\tt{P = 5625}$

Hence, present population of the town is 5625.

Answer 2

Answer:

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Step-by-step explanation:

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