Question

5. The position of particle moving on a
straight line is S=-3t2+2t+6. The velocity of
particle will be zero at time
​

Answer 1

Answer:

Explanation:

s=t³-6t²+3t+7

Let the velocity of the particles be V.

Velocity(V) = ds/dt

∴ V= ds/dt = 3t²-12t+3

Hence,the acceleration of the particles will be :

a = dv/dt

a = 6t-12

But, a = 0

It follows that :

6t-12=0

∴ 6t = 12

∴ t = 2s

Therefore,

V = 3(2)² - 12(2) + 3,when t= 2s

V = 12 - 24 + 3

V = -9m/s

V = 9m/s

Answer 2

Answer:

ds/dt=-6t+2

i.e ds/dt=velocity of particle

0=-6t+2

6t=2

t=1/3 sec