Question

5. The r.m.s. value of pure cosine function is *
0.5 of peak value
0.707 of peak value
Zero
Same as peak value​

Answer 1

Answer:

b) 0.707 of peak value.......

Explanation:

hope it helps u....

Answer 2

Answer:

The r.m.s. value of pure cosine function is 0.707 of peak value .

Explanation:

The peak voltage of a sinusoidal is always divided by the square root of $2$ to get the RMS voltage.

The peak voltage value is multiplied by $0.707$ to get the RMS voltage of a sinusoidal waveform, which is equal to one divided by the square root of two $\frac{1}{2}$.

The formula for the  r.m.s. value of pure cosine function is $V_{r m s}=\frac{V_m}{\sqrt{2}}$ .

The value of $\frac{1}{\sqrt{2} } =0.707$

So we can write $V_{r m s}=\frac{V_m}{\sqrt{2}}= 0.707 V_{m }$.

An alternating quantity's peak value is the highest value it can reach in a cycle.

Here $V_{m}$ is the peak value and we can write the answer as $0.707$ of peak value .

Therefore, the correct choice is option (b) which is 0.707 of peak value .

To know more about "rms value"

https://brainly.in/question/16170928

To know more about "peak value"

https://brainly.in/question/48511597

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