Question

5. The ratio between maximum range and maximum height attained by the projectile for the angle of projection of 45° is O 2:1 3:1 O 1:2 4:1​

Answer 1

Answer:

For complementary angles, range will be same

OR

R

2

R

1

=

[

g

u

2

sin2(45+θ)

]

[

g

u

2

sin2(45−θ)

]

=

u

2

sin(90+2θ)

u

2

sin(90−2θ)

=

cos2θ

cos2θ

=1