5.
The shape of a garden is rectangular in the middle and semi-circular at the ends. Find the area
and the perimeter of this garden.
Answers
which type of questions?
Answer:
We know that,
length of the garden=20 m
diameter of semicircle=7m,r=3.5m
(breadth of the rectangle)
Length of rectangle=
20m-3.5m-3.5m
20m− 3.5m− 3.5m
=13 m
Area of rectangle=
length\times breadth
length× breadth
=13m\times7m
= 13m× 7m
=91\ m^2
= 91 m
2
Area of semi-circle =
2
1
×
π×
(3.5) 2
=
=\frac{1}{2}\times\frac{22}{7}\times\frac{35}{10\ }\times\frac{35}{10}
=
2
1
×
7
22
×
10
35
×
1 0
3 5
=19.25\ m^2
= 19.25 m
2
Area of garden=
91+19.25+19.25
91+ 19.25+ 19.25
=129.5\ m^2
= 129.5 m
2
Perimeter of garden=perimeter of rectangle+2(Perimeter of semicircle)
Perimeter of rectangle=
=2\times length
= 2× length
=2\times26
= 2× 26
=26\ m
= 26 m
Perimeter of semicircle=
=\pi r
=πr
=\frac{22}{7}\times3.5
=
7
22
×
3.5
=\frac{22}{7}\times\frac{35}{10}
=
7
22
×
1 0
3 5
=11m
Perimeter of Garden=26m+11m+11
=48m