5.
The sides of a rectangle are 3 a2 +6b and 4 a2 + b. Fiņd its perimeter?
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6. What should be added to a2 + 2ab + b2 to obtain 2 a2 + 4ab?
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Step-by-step explanation:
5)let, length of the rectangle=3a²+6b
breadth of the rectangle=4a²+4ab
perimeter of the rectangle=2(length+breadth)
=2(3a²+6b+4a²+b)
=2(7a²+7b)
=14a²+14b
6)Let, the number to be added be x
so,x+a²+2ab+b²=2a²+4ab
or,x=(2a²+4ab)-(a²+2ab+b²)
or,x=2a²+4ab-a²-2ab-b²
or,x=a²+2ab-b²
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