Question

5. The sides of an equilateral triangle are
(6x + 3y) cm, (8x + 9y – 5) cm and (10x + 12y -
8) respectively. Find the length of each side.
[Hint. Take 6x + 3y = 8x + 9y - 5 and
8x + 9y – 5 = 10x + 12y - 8 as two equations.]​

Answer 1

Answer:

Step-by-step explanation:

Sides = 6x + 3y) cm, (8x + 9y – 5) cm and (10x + 12y - 8)

Since, sides of equilateral triangle are equal

Take 6x + 3y = 8x + 9y - 5

6x - 8x = 9y - 3y - 5

-2x = 6y - 5

2x + 6y = 5 -----------eq1

8x + 9y – 5 = 10x + 12y - 8

8x - 10x + 9y - 12y = 5 - 8

-2x - 3y = -3 ----------eq2

Multiply eq2 by -1

2x +3y = 3

By elimination method

2x + 6y = 5 -----------eq1

2x +3y = 3 ------------eq2

- - = - subtraction

_______________________

3y = 2

y = 2/3

Put the value of y in eq 1

2x + 3x 2/3 = 5

2x + 2 = 5

x = 1

(6x + 3y) cm, (8x + 9y – 5) cm and (10x + 12y -8)

= (6x1 + 3x2/3)cm , ( 8x1 + 9x2/3 - 5 )cm, ( 10x1 +12x2/3 -8) cm

= 8, 9 , 10 lenght