5. The simple interest on a sum of money for 2 years at 12% per annum is 14400. What
will be the compound interest on that sum at the same rate and for the same time?
6. In how many years will the compound interest on 10000 be 2597.12 at 8% per annum?
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Step-by-step explanation:
It is given that
Simple Interest (SI) = 1380
Rate of interest (R) = 12% p.a.
Period(T)= 2 years
(i) We know that
Sum(P) = (SI×100)/(R×T)
Substituting the values
=(1380×100)/(12×2)
= 5750
(ii) Here
Principal (P)= 5750
Rate of interest (R)= 12% p.a or 6% half- yearly
Period (n) = 1 year - 2 half years
So we get
Amount (A)= P(1 + R/100)
Substituting the values
=5750(1+6/100)
2
By further calculation
= 5750×(53/50)
2
So we get
=5750×53/50×53/50
= 6460.70
Here
Compound interest = A- P
Substituting the values
= 6460.70−5750
= 710.70
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