Question

5. The sum of digits of a two digit number is 11 If the digit at ten's place is increased by
5 and the digit at unit's place is decreased by 5, the digits of the number are found to be
reversed. Find the original number.​

Answer 1

Answer:

Given:

x + y = 11 -----------1

Also given:

10(x + 5) + y - 5 = 10y + x

10x + 50 + y - 5 = 10y + x

10x + y + 45 = 10y + x

9y - 9x = 45

y - x = 5 ---------------2

Adding equation 1 and equation 2

2y = 16

y = 8

Therefore, x = 11 - y = 11 - 8 = 3

Therefore, the two-digit number = 10x + y = 10*3 + 8 = 38