Question

5. The sum of first 16 terms of
the AP: 10, 6, 2,... is​

Answer 1

Answer:

here n= 16 d= -4 and a= 10 then sum is -320

Answer 2

Answer:

$S_{16}=-320$

Step-by-step explanation:

First term=10

Common difference(d)=Second term-First term

Common difference(d)=6-10=-4

N=16

$Sum\:of\:n\:terms=S_{n}=\frac{n}{2}[2a+(n-1)d]$

                             $S_{16}=\frac{16}{2}[2\times10+(16-1)-4$

                             $S_{16}=8[20+15]-4$$S_{16}=8[20+(15\times(-4))]$

                             $S_{16}=8[20+(-60)]$

                             $S_{16}=8[20-60]$

                             $S_{16}=8[-40]$

                             $S_{16}=-320$

Please mark it as brainlist answer