Question

5. The sum of four consecutive integers is 266. What are the integers????
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Answer 1

Answer:

let the first integer be = x

2nd integer= x+1

3rd integer=x+2

fourth integer = x+3

sum of the integers = 266

Equation:

x+x+1+x+2+x+3=266

4x+6=266

4x=266-6=260

x=260/4

x= 65

therefore the integers are:

65 ; 66 ; 67; 68

answer with explanation above

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Answer 2

Answer:

65 66 67 68

Step-by-step explanation:

$x$+($x$+1)+($x$+2)+($x$+3)=266

=4$x$+1+2+3

=4$x$+6=266

=4$x$=266-6

=4$x$=260

=$x$=260\4

==$x$=65

$x$=65     $x$+1=66     $x$+2=67     $x$+3=68

65+66+67+68=266