5.
The sum of the digits of a 2-digit number is 11. The number obtained by ls
interchanging the digits exceeds the original number by 27. Find the number.
tinles
Answers
Answer:
x+ y = 11 (1 EQ.)
10x + y= 10y+x+27 (2EQ.)
from 1 EQ....
x= 11-y
put the value of x in 2 EQ....
10x-x +y-10y= 27
9x - 9y = 27
9( x-y) = 27
x-y = 27 /9
x-y = 3
NOW PUT THE VALUE OF X
x- y = 3
11-y -y = 3
11-2y = 3
-2y= 3-11
-2y = - 8
y= 8/2
y= 4
THEREFORE X= 11-Y
= 11-4
= 7
PLZZ MARK AS BRAINLIEST ANSWER
Answer:
47 and 74
Step-by-step explanation:
As we have given in the question there is a number whose digit sum is 11 and by interchanging its digit the number obtained is exceeded original number by 27. Therefore the question is very easy first of all we have to do is think out of a pair which makes a sum 11
Therefore pairs are
2 and 9
3 and 8
4 and 7
5 and 6
Now we should check all these pairs by interchanging which number we get we get 27 exceeds
So the number is 47 as its sum is also 11 and by interchanging the digits we would get 74 which exceeds 27 from original number i.e. 47