Question

5.
The sum of the digits of a 2-digit number is 11. The number obtained
interchanging the digits exceeds the original number by 27. Find the number​

Answer 1

Step-by-step explanation:

Let the unit place be x and Tens place be y then the number is 10y+x

Given: x+y=11−−(1)

If digits got interchanged then the number exceed by 27

i.e., 10x+y=10y+x+27

9x−9y=27

x−y=3−−−(2)

Solving (1) and (20

we get x=7 y=4

∴ the number is 47

Answer 2

Answer:

47

Step-by-step explanation:

Let the one's digit be x.

ten's digit=11-x

ATQ,

10(11-x)+x+27=10x+11-x

110-10x+x+27=9x+11

137-9x=9x+11

18x=126

x=7

11-x=11-7=4

Req.No.=47