Question

5) The sum of the outer angles of polygon is twice the
sum of the inner angles. How many sides does it have?
What if the sum of outer angles is half the sum of inner
angles? And if the sums are equal?​

Answer 1

Step-by-step explanation:

ABCD is a parallelogram such that AB = 2 AD

E is the midpoint of (AB) and F is the midpoint of [CD]

1) Prove that AEFD and BCFE are rhombuses.

2) Prove that triangle AFB is a right triangle.

HELP ABCD is a parallelogram such that AB = 2 AD

E is the midpoint of (AB) and F is the midpoint of [CD]

1) Prove that AEFD and BCFE are rhombuses.

2) Prove that triangle AFB is a right triangle.

HELP

Answer 2

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Step-by-step explanation:

ANSWER

(i) Sum of interior angles of a polygon =(n−2)∗180

∘

Sum of exterior angles of a regular polygon =360

∘

2(n−2)∗180

∘

=360

∘

n−2=1⇒n=3

(ii) 360

∘

=

2

1

(n−2)180

∘

n−2=4⇒n=6

(iii)(n−2)∗180

∘

=360

∘

n−2=2⇒n=4