Question

5. The tens digit of a two-digit number is 4 times the
digit at the ones place. If the digits are reversed and
the resultant number is added to the original number,
then the sum is 110. Find the original number.​

Answer 1

Answer:

82

Step-by-step explanation:

let the digit at ones place be x.

digit at tens place = 4x

number= 40x+x=41x

if digits are reversed no. = 10x+4x =14x

sum = 41x+14x =55x=110

x= 2

original no. = 41x =41*2

= 82