5. The thickness of the wall of a vessel is 5 cm and its to
surface area is 1000 cm2. To maintain a temperatured
70°C inside the vessel, an electric heater is installer
inside it. If the outside temperature be 20°C, what will
be the power of the heater? The coefficient of therma
10.
conductivity of the wall of the vessel = 0.1 CGS unit.
4200
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Answer:According to fourier Eqn of heat transfer
Power=Qt= −KAΔTlP=−0.1×1000×(70−20)5=1000 calsec/P=4.2*1000=4200 Jsec/=4200Watts
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