Math, asked by naikdaksh10151906, 1 month ago

5. The value of k for the following pair of a linear equation to have no
solution is ________
kx+6y+11=0
5x+10y+7 =0
a) 1
b) 2
c) 3

Answers

Answered by sarang2317
2

Answer:

c) 3

Step-by-step explanation:

a1=k b1=6 c1=11

a2=5 b2=10 c2=1

For no solution

a1/a2 = b1/b2 ≠ c1/c2

So

a1/a2 = k/5

b1/b2 = 3/5

k/5 = 3/5

=> 15 = 5k

k = 15/5 = 3

k = 3

Answered by krish1399
0

Answer:

a1=k b1=6 c1=11

a2=5 b2=10 c2=1

For no solution

a1/a2 = b1/b2 ≠ c1/c2

So

a1/a2 = k/5

b1/b2 = 3/5

k/5 = 3/5

=> 15 = 5k

k = 15/5 = 3

k = 3

Step-by-step explanation:

mark me as brainliest.

Similar questions