Question

5. Three angles of a quadrilateral are in the
ratio 3: 4:5. The difference of the least
and the greatest of these angles is 45º. Find
all the four angles of the quadrilateral.​

Answer 1

Answer:

Let the three angles of the quadrilateral be 3x, 4x and 5x.

[ Given in question ] :-

The difference between the least and the greatest of these angles ( in these three angle ) is 45° .

According to the question :-

5x - 3x = 45°

=> 2x = 45°

=> x = 45/2°

then, measure if these three angle is :-

3x = 3 × 45/2 = 135/2°

4x = 4 × 45/2 = 2 × 45 = 90°

5x = 5 × 45/2 = 225/2°

Fact :- Sum of all angles of a quadrilateral is 360° .

then, let the fourth angle be y

135/2° + 90° + 225/2° + y = 360°

=> 135/2° + 225/2° + 90° + y = 360°

=> 360/2° + 90° + y = 360°

=> 180° + 90° + y = 360°

=> 270° + y = 360°

=> 360° - 270°

=> y = 90°

Hence, fourth angle = y = 90°

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Answer 2

Answer:

heuyy help me fast! the question is in French..Will post it in a few sec..