Question

5. Three girls Rejia, Mary and Nilakshi are playing
a game by standing on a circle of radius 5m
drawn in a park. Rejia throws a ball to Mary,
Mary to Nilakshi, Nilakshi to Rejia. If the
distance between Rejia and Mary and between
Mary and Nilakshi is 6m each, what is the
distance between Rejia and Nilakshi?​

Answer 1

Answer:

ans is 19.4

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Answer 2

Answer:

9.6m

Step-by-step explanation:

let R,M and N be the position . Rezia ,Mary ,Nilakshi

given RM= MN =6

r= 65 m

construction - OR , OM and OL perpendicular RM are drawn

let , RK = X

RM PERPENDICULAR OL bisects it

therfore RL = LM = 3cm

therefore, in rt triangle OLM

OL square + LM square =OM square

= " " + 3 square = square

= ol square = 25 - 9

= root over 16

= 4 cm

now , ar (ORK) = 1/2 × RM ×OL = 1/2 × OM× RK

= 1/2 × 6 ×4=1/2×5× x

= 12 ×2/5 = x

therefore RN = 2 ×24/5 =48/5 = 9.6 cm

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