Question

5. Three girls Reshma, Salma and Mandip are
playing a game by standing on a circle of radius
5m drawn in a park. Reshma throws a ball to
Salma, Salma to Mandip, Mandip to Reshma. If
the distance between Reshma and Salma and
between Salma and Mandip is 6m each, what is
the distance between Reshma and Mandip?
​

Answer 1

Answer:

Draw perpendicular OA and OB on RS and SM respectively.

Let R,S and M be the position of Reshma, Salma and Mandip respectively.

AR=AS=

2

6

=3 cm

OR=OS=OM=5 m [radii of circle]

In △OAR

OA

2

+AR

2

=OR

2

OA

2

+3

2

=5

2

OA=

25−9

OA=4 m

We know that in an isosceles triangle altitude divides the base ,

So, in △RSM

∠RCS=90

o

RC=CM

Area of △ORS=

2

1

×OA×RS

2

1

×RC×OS=

2

1

×4×6

RC×5=24

RC=4.8 m

RM=2RC=2×4.8=9.6 m

So, distance between Reshma and Mandip is 9.6 m

Answer 2

Answer:

this answer was told by my teacher and is 100% correct....