Physics, asked by muzzu280613, 11 months ago

5. Three liquids A, B and C of masses
400gm, 600 gm, and 800 gm, are at
30°C, 40°C and 50°C respectively.
When A and B are mixed resultant
temperature is 36°C when Band C
are mixed resultant temperature is
440C the ratio of their specific
heats are
1) 2:1:1
2) 3:2:1
3) 2:2:1
4) 1:4:9​

Answers

Answered by shloksoni115
10

Answer:

2:2:1

Explanation:

Heat lost = gained = msΔT

A+B

400 (36 - 30) Sa = 600 x (40 - 36) Sb

Sa = Sb

B + C

600 (44-40) Sb = 800 (50-44) Sc

Sb = 2 Sc

Sa : Sb : Sc = 2:2:1

Answered by deepikaavm
7

Ma-mass of A

Mb-mass of B

Mc-mass of C

Sa-specific heat of A

Sb-specific heat of B

Sc-specific heat of C

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