5. Three pieces of timber 49 m, 56 m and 77 m long have to be divided into planks of the
same length. What is the greatest possible length of each plank
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Answer:
Step-by-step explanation:
Hey!!!!
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Here the greatest possible length of each plank
=> Each Plank/HCF(42,49,56)
Thus By Prime Factorisation Method
=> 42 = 2 x 3 x 7
=> 49 = 7²
=> 56 = 2³ x 7
Thus HCF = 7
For Each
=> 42/7 = 6
=> 49/7 = 7
=> 56/7 = 8
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GIVEN 》
Three pieces of timber = 42m, 49m,56m
greatest possible length of each plank = ?
divided into planks of the same length.=?
take HCF,
42 = 2×3×7
49= 7×7
56= 2×2×7
HCF = 7
(divided into planks of the same length = 7m )
= 42/7 = 6
= 49/7 = 7
= 56/7 = 8
(greatest possible length of each plank= 6m, 7m,8m ) ans
=8
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