Math, asked by pinki1181991, 6 months ago

5. Time taken in skipping the rope 50 times ...
lculates the time between two events,
Ive the sums as per instructions.
1/ Khushi was born in year 2010. How old will she be in the year 2022
2. If the manufacturiing date on a bottle of medicine is 20/09/2018
expiry date is 20/09/2020 then for how much time it is safe to ta
medicine?
6. Chandran's cough medicine has expiry date of 15th December, 20%
Chandran take this medicine on 25/10/2020?
. A train arrives at 5:50 a.m. at Surat station. It departs at 6:10 a.
how much time does the train stop on the station?
Preet plays different games in the playground from 5:30 p.m. to
7'o' clock. For how much time does he play?​

Answers

Answered by RvChaudharY50
0

Question 1) Khushi was born in year 2010. How old will she be in the year 2022 ?

Answer :-

→ Khushi was born in = 2010

So,

→ in year 2022 she will be = 2022 - 2010 = 12 years old.(Ans.)

Question 2) :- If the manufacturiing date on a bottle of medicine is 20/09/2018 and expiry date is 20/09/2020 then for how much time it is safe to take the medicine ?

Answer :-

→ manufacturiing date of medicine = 20 - 09 - 2018

→ Expiry date of medicine = 20 - 09 - 2020 .

So,

→ Time period for medicine is safe = (20 - 09 - 2020) - (20 - 09 - 2018) = 2 years. (Ans.)

Question 3) :- Chandran's cough medicine has expiry date of 15th December, 2020. Can Chandran take this medicine on 25/10/2020 ?

Answer :-

→ Expiry date of medicine = 15th december 2020 .

→ Chandran want to take medicine on = 25 oct. 2020 .

So,

Yes , Chandran can take medicine on 25/10/2020, as for expiry date still 1 month 20 days left.

Question 4) :- A train arrives at 5:50 a.m. at Surat station. It departs at 6:10 a.m how much time does the train stop on the station ?

Answer :-

Train arrives at station = 5 : 50AM

→ Train departs at = 6: 10 AM.

So,

Time for the train stop on the station = 6 : 10 - 5 : 50 = 5 : 70 - 5 : 50 = 20 minutes. (Ans.)

Question 5) :- Preet plays different games in the playground from 5:30 p.m. to 7'o' clock. For how much time does he play ?

Solution :-

→ Preet went to playground = 5 : 30 PM.

→ Preet plays games upto = 7 : 00 PM .

So,

→ Time for which Preet play = 7 : 00 - 5 : 30 = 6 : 60 - 5 : 30 = 1 : 30 hours. (Ans.)

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