Question

5 times of a number is 3 less than the twice of its square then find original number

Answer 1

Answer:

let the number be x,

ATQ,

5x=2x2-3

2x2-5x-3=0

2x2-6x +x-3=0

2x(x-3)-(x-3)=0

(x-3)(2x-1)=0

x=3. ,x=1/2

I hope it would help you.

thanking you.

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