Question

5 times positive number is less than its square by 24 what is the integer

Answer 1

↑ Here is your answer ↓
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Let that integer be 'x',

$5x = x^2 - 24$

$x^2 - 24 - 5x = 0$

$x^2 - 5x - 24 = 0$

Lets solve now,

$x^2 - 8x + 3x - 24 = 0$

$x(x-8) +3(x-8) = 0$

$(x-8)(x+3) = 0$

Hence,

$x = 8, x = -3$

Answer 2

let the positive integer = x

according to given information

5x = x^2 - 24
x^2 - 5x - 24=0
x^2 - 8x + 3x - 24 =0
x(x-8) + 3(x - 8) = 0
(x +3) (x - 8)=0
x = -3 , x = 8

-3 is not positive integer....so 8 is an positive..


So the integer is 8
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#Hope its help you..#