5 times the age of a man is 12 times the age of his son 5 years ago the ratio of their ages is 11:4 find the present ages
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the age will be 55 years
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Let the age of man = x
and that of son = y
According to the question :
5x = 12y
5x - 12y = 0 ...[ Equation 1 ]
Before 5 years,
Ages of man = x - 5
Ages of son = y - 5 .
x - 5 / y - 5 = 11 : 4
4 ( x - 5 ) = 11 ( y - 5 )
4x - 20 = 11y - 55
4x - 11y = 20 -55
4x - 11y = -35 .... [ Equation 2 ]
Equation ( 1 ) * 4 = 20x - 48y = 0
Equation ( 2 ) * 5 = 20x - 55y = -175
Subtracting both of them, 7y = 175 , y = 25 .
5x = 12y
5x = 12 ( 25 )
x = 60
Now, Age of Man = 60 , Age of his son = 25 .
and that of son = y
According to the question :
5x = 12y
5x - 12y = 0 ...[ Equation 1 ]
Before 5 years,
Ages of man = x - 5
Ages of son = y - 5 .
x - 5 / y - 5 = 11 : 4
4 ( x - 5 ) = 11 ( y - 5 )
4x - 20 = 11y - 55
4x - 11y = 20 -55
4x - 11y = -35 .... [ Equation 2 ]
Equation ( 1 ) * 4 = 20x - 48y = 0
Equation ( 2 ) * 5 = 20x - 55y = -175
Subtracting both of them, 7y = 175 , y = 25 .
5x = 12y
5x = 12 ( 25 )
x = 60
Now, Age of Man = 60 , Age of his son = 25 .
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