Math, asked by biosreaper14, 8 months ago

5. Triangle ABC is right-angled at C and CD is perpendicular to AB, prove that
BC'S ADACBD​

Answers

Answered by priyankadanu113
0

Step-by-step explanation:

ANSWER

Consider △ACD&△ABC

∠CAD=∠CAB

∠CDA=∠ACB

∴△ACD∼△ABC,{ By AA similarty criterion}

AB

AA

=

AC

AD

∴AC

2

=AB×AD−(1)

Similarily,△BCD∼△BAC{ by AA similarity criterion}

BA

BC

=

BC

BD

∴BC

2

=BA×BD−(2)

AC

2

BC

2

=

AB×AD

AB×BD

∴BC

2

×AD=AC

2

×BD

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