Question

5. Two adjacent sides of a parallelogram have
lengths 12 cm and 8 cm. The distance between the two longer sides is 6 cm. Find
the area of the parallelogram and the distance between the two shorter sides.

Answer-72 cm²,9cm
please explain it step by step that how this answer come​

Answer 1

Answer:

Area of Parallelogram = Base × Height = 8×6=48cm

2

So Distance between two shorter sides =

12

48

=4cm

Step-by-step explanation:

please upvote and thanks me and mark me a Brain liest

Answer 2

$\star\underline{\mathtt\orange{⫷❥Q᭄} \mathfrak\blue{u~ }\mathfrak\blue{Σ} \mathbb\purple{ §}\mathtt\orange{T} \mathbb?\pink{iOn⫸}}\star\:$

Two adjacent sides of a parallelogram have

lengths 12 cm and 8 cm. The distance between the two longer sides is 6 cm. Find

the area of the parallelogram and the distance between the two shorter sides.

$\star\underbrace{\mathtt\red{⫷❥ᴀ᭄} \mathtt\green{n~ }\mathtt\blue{ §} \mathtt\purple{₩}\mathtt\orange{Σ} \mathtt\pink{R⫸}}\star\:$

${ { \underbrace{ \mathbb{ \red{GiVeN:-\ }}}}}$

$two \: adjacent \: sides \: of \: a \: parallelogram \: are \\ AB = 12cm \\ BC = 8cm$

$distance \: between \: the \: two \: longer \: sides \\ DE = 6cm$

${ { \underbrace{ \mathbb{ \red{To\:PrOvE\ }}}}}$

$area \: of \: the \: parallelogram \\ \\ distance \: between \: the \: 2 \: shorter \: sides$

${ \color{aqua}{ \underbrace{ \underline{ \color{lime}{ \mathbb{✯꧁ ⋆᭄ SoLuTiOn⋆᭄꧂✯ }}}}}}$

$let \: the \: distance \: between \: the \: 2 \: shorter \: \\ DF = x$

$area \: of \: parallelogram = base \times height$

$considering \: AB \: as \: the \: base$

$a = bh$

$= 12 \times 6$

$= 72 {cm}^{2}$

$now \: considering \: BC \: as \: the \: base$

$a = bh$

$= 8 \times x$

$= 8x$

$areas \: of \: parallelogram \: are \: same$

$72 = 8x$

$x = \frac{72}{8}$

$x = 9cm$

$x = DF = 9cm$

$area \: of \: parallelogram = 72 {cm}^{2}$

$distance \: between \: the \: 2 \: shorter \: sides = 9cm$

$\blue{\boxed{\blue{ \bold{\fcolorbox{red}{black}{\green{☺︎︎Hope\:It\:Helps☺︎︎}}}}}}$

${\mathbb{\colorbox {orange} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {lime} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {aqua} {@suraj5069}}}}}}}}}}}}}}}$