Question

-5. Two cars A and B move such that car A moving with
a uniform velocity of 15 ms over takes car B mov-
ing from rest with an acceleration of 3 ms. The
time, after which, they meet again, is​

Answer 1

Refer to attachment:

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Answer 2

Answer:

Let us assume that the car A and B meet after a time 't'.

Distance travelled by A in that time is 'vt' =15t

distance travel by B

$s = ut + \frac{1}{2} a {t}^{2}$

$s = \frac{3 {t}^{2} }{2}$

$\frac{3 {t}^{2} }{2} = 15t$

t =0, 10s

➡ at 10sec both the car meet.