Question

5.
Two coins are tossed simultaneously. The probability of getting at most
one head is
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Answer 1

YOUR ANSWER IS 3/4.

EXPLANATION:-

Given -

Two coins are tossed simultaneously.

So the outcomes will be-

(H,H), (H,T), (T,T), (T,H)

Where H stands for Heads and T stands for Tails.

Clearly from above we can see that the number of outcomes of getting atmost ine head is 3 i.e. (T,T), (T,H), (H,T)

And total number of outcomes are 4

So the probability of getting at most once head=Number of outcomes of getting at most one head/ Total number of outcomes

=3/4.

Hope this will help you if it it helps then plz mark my answer as BRAINLIEST. And remember to always keep a smile on face.

Answer 2

Probability of getting at most  one head is $\frac{3}{4}$ .

Step-by-step explanation:

We are given that Two coins are tossed simultaneously and we have to find the probability of getting at most  one head ;

Firstly, we will find that what outcomes are are when two coins are tossed simultaneously;

Outcomes after tossing two coins are given as;

1. Head on both the coins : {Head, Head}
2. Tails on both the coins : {Tail, Tail}
3. Head on one coin and tail on another coin : {Head,Tail} and {Tail, Head}

It means there are total 4 outcomes on tossing two coins.

Now, we are interested in getting at most 1 head means we are not interested in the case when head appears on both the coins,i.e.; {Head, Head}

So, number of favorable cases of at most one head = {Tail, Tail} , {Head,Tail} , {Tail, Head}

Probability for any event is = Favorable outcomes ÷ Total no. of outcomes

Therefore, probability of getting at most  one head = $\frac{3}{4}$ .