5. Two electric charges one 15 times as strong as the other, exert a force 2.45×10-2 on each other. When they are placed 10 cm apart in air, find the magnitude of each charge.
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PHYSICS
Two point charges exert on each other a force F when they are placed r distant apart in air. When they are placed R distance apart in a medium of dielectric constant K, they were exerting the same force. The distance R equals
December 27, 2019avatar
Sushil Ruhela
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ANSWER
Given two point charges exert a force F when placed r apart in air. When they are placed R apart inn a medium of dielectric constant K, the force between them is same. We have to find R.
For this, let q
1
and q
2
be two point charges. When these charges are placed in dielectric medium, then force is
4πε
1
R
2
q
1
q
2
where
ε
0
ε
=K= dielectric constant of the medium.
So, new force =
4πε
0
K
1
R
2
q
1
q
2
when placed in air, F=
4πε
0
1
r
2
q
1
q
2
ε= permittivity of medium
ε
0
= permittivity of air
Given that force in both the cases is same; then
4πε
1
r
2
q
1
q
2
=
4πε
1
KR
2
q
1
q
2
r
2
=KR
2
So, R=
K
r