Question

5.
Two numbers are in the ratio 4:2. If they differ by 16, what are the numbers?​

Answer 1

Given :- Two numbers are in the ratio 4:2. If they differ by 16, what are the numbers ?

Solution :-

Let us assume that, given two numbers are 4x and 2x respectively .

So,

→ Difference of numbers = 16

→ 4x - 2x = 16

→ 2x = 16

dividing both sides by 2,

→ x = 8 .

Therefore,

• First number = 4x = 4 * 8 = 32 .
• Second number = 2x = 2 * 8 = 16 .

Hence, required two numbers are 32 and 16 .

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Answer 2

$\Large{\underline{\underline{\bf{QuEsTiOn:-}}}}$

❥Two numbers are in the ratio 4:2. If they differ by 16, what are the numbers ?

$\Large{\underline{\underline{\bf{AnSweR:-}}}}$

❥ The two numbers are 32 and 16.

$\Large{\underline{\underline{\bf{GiVen:-}}}}$

➽ Ratio of the numbers 4 : 2.

Which are differ by 16 .

$\Large{\underline{\underline{\bf{To find :-}}}}$

❥ what are the numbers?

$\Large{\boxed{\underline{\overline{\mathfrak{\star \: SoLuTioN :- \: \star}}}}}$

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✒ Let us consider the ratio of two numbers be x

✒ The two numbers are 4x and 2x

✒ Since two numbers differ by 16,

❥ we can write the equation

✒ 4x – 2x = 16

✒ 2x = 16

✒ x = 16/2

✒ x = 8

Now,

✒ put the value of x .

☛ 1st no. ↠ 4x = 4 x 8 = 32

☛ 2nd no. ↠ 2x = 2 x 8 = 16

Therefore ,

➽ The two numbers are 32 and 16.

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