Math, asked by jodhrajb8, 4 months ago

5 Two numbers are in the ratio 5:3. If they differ by 18, what are the numbers
6. Three consecutive integers add up to 51. What are these integers?
im of three consecutive multiples of 8 is 888. Find the multiples.​

Answers

Answered by VedaantSengar317
2

Answer:

5. 45 and 27

6. 16, 17 and 18

Step-by-step explanation:

5.

Let us assume the numbers to be 5x and 3x

Difference of the numbers = 18   (Given)

Therefore, we can write that

5x - 3x = 18

2x = 18

x = 18 / 2

x = 9

We know that the first number if 5x and second number is 3x

Therefore,

1st Number = 5(9) = 45

2nd number = 3(9) = 27

***

6.

Let us assume the three consecutive integers to be (x), (x + 1) and (x + 2)

Sum of the integers = 51

Therefore we can write that,

x + (x + 1) + (x + 2) = 51

x + x + 1 + x + 2 = 51

3x + 3 = 51

3x = 51 - 3

x = 48 / 3

x = 16

We know that the first number is x, second number is (x + 1) and the third number is (x + 2)

Therefore,

1st number = x = 16

2nd number = (x + 1) = (16 + 1) = 17

3rd number = (x + 2) = (16 + 2) = 18

Hope these answers help you.

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