Physics, asked by akanshaamishraa, 1 year ago

5. Two particles A and B are moving in

XY-plane. Their positions vary with time t

according to the relation :

xA

(t) = 3t, xB

(t) = 6

yA

(t) = t, yB

(t) = 2 + 3t2

The distance between the two particles at t=1

is

(1) 5 (2) 3 (3) 4 (4) 12​

Answers

Answered by aneesakhtar117
7

Answer:

Explanation:

xA=3t,yA=t

At t=1,xA=3andyA=1

So, coordinates of article A is (3,1).

xB=6,yB=2+3t2

At t=1,xB=6andyB=5

So, coordinates of article B is (6,5).

∴ Distance between A and B=(6−3)2+(5−1)2−−−−−−−−−−−−−−−√=25−−√=5.

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