Question

5. Two stations P and Q are at a distance of 160 km. Two trains start moving from P and Q to Q and P, respectively and meet each other after 4 h. If speed of the train starting from Pis more than that of other train by 6 km/h, then find the speed of both the trains, respectively. (a) 19 km/h 13 km/h (b) 13 km/h, 9 km/h (c) 17 km/h, 23 km/h (d) 16 km/h, 10 km/h (e) None of the above​

Answer 1

Solution :

Let two trains be

• Train A started from P

• Train B started from Q

Given :

Total distance = 160km

Time = 4 hour

• Let the speed of train B = x

⇒ Speed of train A = x + 6km/h

• Formula -

Speed = distance/time

⇒ Speed of train B = 160/4

⇒ Speed = 40km/h

∴ Speed of train B = 40km/h

Since,

• Speed of train A = Speed of train B + 6km/h

⇒ Speed = 40km/h + 6km/h

⇒ Speed = 46km/h

∴ Speed of train A = 46km/h

⇒ Speed of train A and B

= 46km/h , 40km/h

Answer)

• e) none of the above

Answer 2

Solution :

Let two trains be

• Train A started from P

• Train B started from Q

Given :

Total distance = 160km

Time = 4 hour

• Let the speed of train B = x

⇒ Speed of train A = x + 6km/h

• Formula -

Speed = distance/time

⇒ Speed of train B = 160/4

⇒ Speed = 40km/h

∴ Speed of train B = 40km/h

Since,

• Speed of train A = Speed of train B + 6km/h

⇒ Speed = 40km/h + 6km/h

⇒ Speed = 46km/h

∴ Speed of train A = 46km/h

⇒ Speed of train A and B

= 46km/h , 40km/h

Answer)

• e) none of the above