Math, asked by sudi6050, 7 months ago

(5 underroot 3 +4 underroot 3)+ ( 2 underroot 2 + 5 underroot 2)

Answers

Answered by tofailahmad379
1

Answer:

(5 underroot 3 +4 underroot 3)+ ( 2 underroot 2 + 5 underroot 2)

5(3)^1/2 + 4(3)^1/2 + 2(2)^1/2+ 5(2)^1/2

Take common

(5+4)(3)^1/2 + (2+5)(2)^1/2

9(3)^1/2 + 7(2)^1/2

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