Question

5 upon root 3 - root 5​

Answer 1

Answer:

we will rationalise the denominator

$\frac{5}{ \sqrt{3 } - \sqrt{5} } \times \frac{ \sqrt{3} + \sqrt{5} }{ \sqrt{3} + \sqrt{5} } \\ by \: using \: identity \: in \: denomitor \\ \frac{5 \sqrt{3} + 5 \sqrt{5} }{(a {}^{2} - b {}^{2} )}$

$\frac{5 \sqrt{3} + 5 \sqrt{5} }{( \sqrt{3} {})^{2} - ( \sqrt{5}) {}^{2} } = \frac{5 \sqrt{3} + 5 \sqrt{5} }{3 - 5} \\ \frac{5 \sqrt{3} + 5 \sqrt{5} }{ - 2}$

$this \: is \: your \: answer$

Answer 2

Answer:

$\frac{5}{ \sqrt{3} - \sqrt{5} } \times \frac{ \sqrt{3} + \sqrt{5} }{ \sqrt{3} + \sqrt{5} } = \frac{5 \sqrt{3} + 5 \sqrt{5} }{(a) {}^{2} - (b) {}^{2} }$

$\frac{5 \sqrt{3} + 5 \sqrt{5} }{( \sqrt{3}) {}^{2} - ( \sqrt{5}) {}^{2} } = \frac{5 \sqrt{3} +5 \sqrt{5} }{3 - 5}$

$\frac{5 \sqrt{3} + 5 \sqrt{5} }{ - 2} = \frac{ - (5 \sqrt{3} + 5 \sqrt{5}) }{2} = \frac{ - 5 \sqrt{3} - 5 \sqrt{5} }{2}$

THIS IS YOUR ANSWER

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