Question

5. Use the distributive property to find each product.
(a) 9x15
(b) 82 x 103
(C) 7x 124
(d) 3807 x 8
(e) 869×10005
(f)258 x 1008 ​

Answer 1

$\underline{\pink{ Distributive \: property :}}$

$If \: a,b,c \in Z \:then$

$\boxed{\blue{ a(b+c) = a \times b + a \times c }}$

$\red{ a) product \: of \: 9 \times 15 }$

$= 9\times ( 10 + 5 )$

$= 9\times 10 + 9 \times 5$

$= 90 + 45$

$= 135$

Therefore.,

$\red{ product \: of \: 9 \times 15 }\green { = 135 }$

$\red{ b) product \: of \: 82\times 103 }$

$= 82\times ( 100 + 3 )$

$= 82\times 100 + 82 \times 3$

$= 8200 + 246$

$= 8446$

Therefore.,

$\red{ product \: of \: 82\times 103}\green { = 8446}$

$\red{ e) product \: of \: 869\times 10005 }$

$= 869\times ( 10000 + 5 )$

$= 869\times 10000 + 869 \times 5$

$= 8690000 + 4345$

$= 869435$

Therefore.,

$\red{ product \: of \: 869\times 10005}\green { = 869435}$

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Answer 2

Answer:

135

Step-by-step explanation:

9×(10+5)

9×10+9×5

90+45=135