Question

5. Using prime factorisation, find the HCF and
(i) 8,9, 25
(ii) 12, 15, 21
(iii) 17, 23 ,29​

Answer 1

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Using prime factorisation, find the HCF and

i) 8, 9 and 25

Factor of 8 = 2×2×2×1

Factor of 9 = 3×3×1

Factor of 25=5×5×1

HCF (8,9,25) = 1

ii)12, 15, 21

Factor of 12 = 2×2×3

Factor of 15 = 3×5

Factor of 21 = 3×7

HCF (12,15,21) = 3

iii) 17, 23 ,29

Factor of 17 = 1×17

Factor of 23 = 1×23

Factor of 29 = 1×29

HCF (17,23,29) = 1

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Answer 2

Answer & Solution is in this picture!!!

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