Question

5) Using the graph given, answer the following question
a. What is the distance covered at the end of 5 sec
b. At what time the object has coved 8m
c. Calculate the acceleration of the object.
201
16
12
Velocity (m/s)
8
4
0
0
1
4
5
2
3
Time (s)​

Answer 1

Explanation:

Correct option is

A

300

(a)Since velocity is not changing, acceleration is equal to zero.

(b) Reading the graph, velocity=20ms

−1

(c) s = area of the figure enclosed under v-t graph. Distance covered in 15s, s=ut=20×15=300m