Question

5. [V (NH3)6]3+ ion hybridisation​

Answer 1

Answer:

sp3d2 is the hybridisation

Answer 2

Answer: The [V (NH3)6]3+ ion hybridization is octahedral (sp3d2).

Explanation:

• Octahedral hybridisation involves six sp3 orbitals, which all lie in the equatorial plane and two orbitals which lie along the axial positions.
• This hybridisation is formed when the central atom has six electron groups surrounding it and the electron groups are all in the same plane. It is the most common hybridisation for transition metal complexes. The hybrid orbitals are all of equal energy.
• Octahedral hybridisation is important in the formation of compounds like [V (NH3)6]3+, as the six electron groups around the Vanadium atom all lie in the same plane.
• This arrangement ensures that the Vanadium atom is surrounded by the same number of electron groups, as well as the same number of electron pairs, ensuring maximal stability of the ion.
• The six sp3 orbitals also ensure that all of the electron groups are located in the same plane, forming an octahedral structure.
• The hybridisation of the [V (NH3)6]3+ ion is important for its stability. Without the octahedral hybridisation, the Vanadium atom would not be surrounded by the same

#SPJ3