Question

5 व 0 हे अंक कितीही वेळा वापरून 11 ने भाग जाणाऱ्या चार अंकी संख्यांची बेरीज किती?​

Answer 1

Answer:

6 7 8 9 is the right answer

Answer 2

To Find :- What is the sum of the four digit numbers divided by 11 using the numbers 5 and 0 any number of times ?

Solution :-

we need to make a four digits number using 5 and 0 . since 0 can't be at thousand place.

so,

→ Thousand's place = only 1 number = 5

now,

→ At hundred's place = 0 or 5 = 2 number .

→ At ten's place = 0 or 5 = 2 number .

→ At unit place = 0 or 5 = 2 number .

then,

→ Total possible 4 digit numbers formed = 1 * 2 * 2 * 2 = 8

These 4 digits number formed are :-

• 5000
• 5005
• 5050
• 5055
• 5500
• 5505
• 5550
• 5555

now, we know that,

• A number is divisible by 11 if :- (sum of digits at even place - sum of digits at odd place = 0, 11, 22 ___)

checking 4 digits number formed we get,

→ 5000 = (5 + 0) - (0 + 0) = 5 ≠ 0 , 11 , 22 .

→ 5005 = (5 + 0) - (0 + 5) = 5 - 5 = 0 = Divisible by 11 .

→ 5050 = (5 + 5) - (0 + 0) = 25 ≠ 0 , 11 , 22 .

→ 5055 = (5 + 5) - (0 + 5) = 10 - 5 = 5 ≠ 0 , 11 , 22 .

→ 5500 = (5 + 0) - (5 + 0) = 5 - 5 = 0 = Divisible by 11 .

→ 5505 = (5 + 0) - (5 + 5) = 5 - 10 = -5 ≠ 0 , 11 , 22 .

→ 5550 = (5 + 5) - (5 + 5) = 10 - 5 = 5 ≠ 0 , 11 , 22 .

→ 5555 = (5 + 5) - (5 + 5) = 10 - 10 = 0 = Divisible by 11 .

therefore,

→ Required sum = 5005 + 5500 + 5555 = 16060 (Ans.)

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