Question

5.
Value of P for which (? – 10x + P) is exactly divisible by (x - 2) is :
यदि 2 - 10r + P (-2) से पूर्णरूप से विभाजित है तो P का मूल्य है
(a) 18
(b) 17
(c)
16
(d)/19​

Answer 1

Answer:

a) 18

Step-by-step explanation:

Substituting x = 2 in the equation

2 - 10(2) + p = 0

2 - 20 + p = 0

-18 + p = 0

p = 18

Hence the value of p is 18

Answer 2

Given  : (x^2 - 10x + P) is exactly divisible by (x-2)

To find : Value of p

Solution:

Long division method :

                x  - 8

(x-2)   _|   (x^2 - 10x + P) | _

                 x²  - 2x

               ________

                       -8x + p

                       -8x + 16

                    ______

                            p - 16

Remainder must be zero hence

p - 16 = 0

=> p = 16

Method 2 :

divisible by x - 2 hence  x - 2 is a factor          

x -  2 = 0  => x = 2

Substituting x = 2 in expression we must get 0

Hence 2² - 10(2) + p = 0

=> 4 - 20 + p = 0

=> p = 16

Hence Value of p is 16

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