Question

5. Verify whether –2 and 3 are zeroes of the polynomial x2 - x - 6.
6. If x= 3/2 is the zeroes of the polynomial 2x2 + kor + 2, then evaluate the value of k.​

Answer 1

Step-by-step explanation:

$x {}^{2} - x - 6 \\ x = - 2 \\ - 2 {}^{2} - ( - 2) - 6 = 4 + 2 - 6 = 0 \\ x = 3 \\ 3 {}^{2} - 3 + 6 = 9 - 3 + 6 = 0$

x=3/2

2×(3/2)^2+k3/2+2=0

9/2+3k/2+2=0

9+3k+4=0

3k=-4-9=-13

k=-13/3