Question

5) Volume of Hcl gas formed when 2
liters hydrogen reacts completely
with 2 dm3 of chlorine gas is
O A) 2 dm3
O B) 6 dm3
C) 1 dm3
O D) 4 dm3​

Answer 1

To find:

Volume of HCl gas formed when 2 litres hydrogen reacts completely with 2 dm³ of chlorine gas.

Calculation:

$H_{2}+Cl_{2}\rightarrow 2HCl$

So, 2 litres of $H_{2}\:\equiv$ 2 dm³ volume.

Now, At STP ,

22.4 dm³ $H_{2}$ reacts with 22.4 dm³ $Cl_{2}$ to produce 44.8 dm³ of HCl.

Now, any reactant can be used in this stoichiometry. As both are in proportion.

So, 2 dm³ of $Cl_{2}$ will give

$= \dfrac{44.8}{22.4} \times 2$

= 4 dm³ volume of HCl.

So, 4 dm³ of HCl is produced.