Question

5) water at 25c is flowing through a 1.0 km long g.I pipe of 200 mm diameter at the rate of 0.07 m3/s. Determine the pumping power (in kw) required to maintain the flow

Answer 1

Answer:

The pumping power required to maintain flow is 17.2 kW.

Given:

Temperature of water = 25°C

Length of the galvanized pipe = L = 1.0 km = 1000 m

Diameter of the galvanized pipe = D = 200 mm = 0.2 m

Flow rate = Q = 0.07  

Friction factor = f = 0.02

Density of the water = ρ = 1000  

To find:

Pumping power =P = ?

Formula used:

Power:

Pressure Drop:

Where,

V is velocity of the flow

Solution:

Now, the pressure drop is:

The velocity of the flow is given as:

Where,

Q is flow rate and A is cross sectional area of pipe

Cross section area of pipe is:

Now, the velocity of the flow is:

Now, the formula of pressure drop becomes,

Now, on substituting the know values,

Now, the pumping power is:  17.4

hope it helps u !!